document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177434>Question 177434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with eliminations please. I have to find out what x or y is to get the other variable. The problem is 18x-18y=0<BR>\n" );
document.write( "                               12x-12y=-12<BR>\n" );
document.write( "I've tried multiplying the top by 12 and the bottom by 12 and i've also tried multiplying the top by 18 and then trying to solve it but both times I still have 2 variables left. How do I use eliminations when if I multiply it I will get the same on both sides and sometimes on top and bottom?<BR>\n" );
document.write( "Thank you for helping me. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132512 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> actually you dont need to multiply by that high of a number...the LCM of 12 and 18 is 36<BR>\n" );
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document.write( "so if you multiply the top by -2 and the bottom by 3 you will eliminate the x terms<BR>\n" );
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document.write( "18x-18y=0<BR>\n" );
document.write( "12x-12y=-12<BR>\n" );
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document.write( "-2(18x-18y=0)---->-36x+36y=0<BR>\n" );
document.write( " 3(12x+12y=-12)--> 36x+36y=-36<BR>\n" );
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document.write( "and now you just add the two equations together thus eliminating the x terms and then solve for y. once you have the solution for y you plug that back into either equation to find x.<BR>\n" );
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document.write( "remember you dont have to multiply both equations by the same number.<BR>\n" );
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document.write( "when you multiply all terms in and equation, by a constant, it doesnt change the equation. in other words x+y=3 is the same linear equation as <BR>\n" );
document.write( "3(x+y=3)--->3x+3y=9.<BR>\n" );
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