document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24811>Question 24811</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Problem says to find an equation of a circle that is tangent to both axes, has it's center in the second quadrant, & has a radius of 3. Thank you for your help!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13250 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Starting with the standard form of the equation for a circle with centre at (h, k) and radius, r:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x+-+h%29%5E2+%2B+%28y+-+h%29%5E2+=+r%5E2 ALIGN=MIDDLE  ALT=\"%28x+-+h%29%5E2+%2B+%28y+-+h%29%5E2+=+r%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You are given the radius, so <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+3 ALIGN=MIDDLE  ALT=\"r+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r%5E2+=+9 ALIGN=MIDDLE  ALT=\"r%5E2+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The circle is tangent to both the x-axis and the y-axis in quadrant II, so by inspection you can see that the centre is located at (-3, 3) so h = -3 and k = 3.<BR>\n" );
document.write( "The equation therefore is:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x+%2B+3%29%5E2+%2B+%28y+-+3%29%5E2+=+9 ALIGN=MIDDLE  ALT=\"%28x+%2B+3%29%5E2+%2B+%28y+-+3%29%5E2+=+9\"   DISABLED_style= \"max-width:90%; height:auto;\" >  </SPAN>\n" );
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