document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177444>Question 177444</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hopefully I've submitted this in the right place to transform a logarithmic expression.\r<BR>\n" );
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document.write( "Express log x 4/9 in terms of log x 3/2\r<BR>\n" );
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document.write( "I worked it out through guesswork as,  -2 log x 3/2,  but can anyone explain the answer and if this is correct.\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132486 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Express log(base x) 4/9 in terms of log(base x) 3/2 <BR>\n" );
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document.write( "log(basex) 4/9\r<BR>\n" );
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document.write( "= log(basex) (2/3)^2\r<BR>\n" );
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document.write( "= log(basex) (3/2)^(-2)\r<BR>\n" );
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document.write( "= -2log(basex) (3/2)\r<BR>\n" );
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document.write( "===========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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