document.write( "Question 177442: My daughter missed this class friday and has a final monday morning..can you please show how to get answer and correct answer? A 20g sample of a radioactive substance has a half life of 28 days.
\n" ); document.write( "a. how much of the sample is left after one year?
\n" ); document.write( "b. how many days will it take for the sample to reach 1 gram?\r
\n" ); document.write( "\n" ); document.write( "Thank you for your help!
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Algebra.Com's Answer #132484 by stanbon(75887)\"\" \"About 
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My daughter missed this class friday and has a final monday morning..can you please show how to get answer and correct answer? A 20g sample of a radioactive substance has a half life of 28 days.
\n" ); document.write( "a. how much of the sample is left after one year?
\n" ); document.write( "A(t) = Ao(1/2)^(t/n) where n is the half-life
\n" ); document.write( "A(365) = 20(1/2)^(365/28)
\n" ); document.write( "A(365) = 20(1/2)^(13.036)
\n" ); document.write( "A(365) = 20*0.0001191
\n" ); document.write( "A(365) = 0.00238 grams
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\n" ); document.write( "Let me know if you cannot follow the logic of this solution.
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\n" ); document.write( "\n" ); document.write( "b. how many days will it take for the sample to reach 1 gram?
\n" ); document.write( "1 = 20(1/2)^(t/28)
\n" ); document.write( "1/20 = (1/2)^(t/28)
\n" ); document.write( "Take the log of both sides to get:
\n" ); document.write( "(t/28)log(1/2) = log(1/20)
\n" ); document.write( "t/28 = log(1/20)/log(1/2)
\n" ); document.write( "t/28 = 4.3219..
\n" ); document.write( "t = 28*4.3219 = 121.013 days
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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