document.write( "Question 177442: My daughter missed this class friday and has a final monday morning..can you please show how to get answer and correct answer? A 20g sample of a radioactive substance has a half life of 28 days.
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document.write( "a. how much of the sample is left after one year?
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document.write( "b. how many days will it take for the sample to reach 1 gram?\r
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document.write( "Thank you for your help! \n" );
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Algebra.Com's Answer #132484 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! My daughter missed this class friday and has a final monday morning..can you please show how to get answer and correct answer? A 20g sample of a radioactive substance has a half life of 28 days. \n" ); document.write( "a. how much of the sample is left after one year? \n" ); document.write( "A(t) = Ao(1/2)^(t/n) where n is the half-life \n" ); document.write( "A(365) = 20(1/2)^(365/28) \n" ); document.write( "A(365) = 20(1/2)^(13.036) \n" ); document.write( "A(365) = 20*0.0001191 \n" ); document.write( "A(365) = 0.00238 grams \n" ); document.write( "---------------------------- \n" ); document.write( "Let me know if you cannot follow the logic of this solution. \n" ); document.write( "----------------------------------------------------------------\r \n" ); document.write( "\n" ); document.write( "b. how many days will it take for the sample to reach 1 gram? \n" ); document.write( "1 = 20(1/2)^(t/28) \n" ); document.write( "1/20 = (1/2)^(t/28) \n" ); document.write( "Take the log of both sides to get: \n" ); document.write( "(t/28)log(1/2) = log(1/20) \n" ); document.write( "t/28 = log(1/20)/log(1/2) \n" ); document.write( "t/28 = 4.3219.. \n" ); document.write( "t = 28*4.3219 = 121.013 days \n" ); document.write( "================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |