document.write( "Question 177428: I've tried different ways to write an equation but am having no luck. Can anyone help?\r
\n" ); document.write( "\n" ); document.write( "A tennis ball dropped onto a hard surface rebounds exactly 2/3 the height from which it falls. How far will it rebound after hitting the surface for the third time if it is dropped from an initial height of 18 feet? \n" ); document.write( "

Algebra.Com's Answer #132482 by solver91311(24713) $\"\"$ $\"About$

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The first time it falls, it rebounds to $\"%282%2F3%29h\"$ if $\"h\"$ is the initial height. For the second time, $\"h\"$ is no longer the initial height, $\"%282%2F3%29h\"$ is, so the rebound height becomes $\"%282%2F3%29%282%2F3%29h\"$ or $\"%282%2F3%29%5E2h\"$ . In general, the rebound height for the $\"n\"$ th bounce is $\"%28%282%2F3%29%5En%29h\"$ . Therefore, you need to calculate $\"%28%282%2F3%29%5E3%2918\"$ \n" ); document.write( "

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