document.write( "Question 177428: I've tried different ways to write an equation but am having no luck. Can anyone help?\r
\n" ); document.write( "\n" ); document.write( "A tennis ball dropped onto a hard surface rebounds exactly 2/3 the height from which it falls. How far will it rebound after hitting the surface for the third time if it is dropped from an initial height of 18 feet?
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Algebra.Com's Answer #132466 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
After the first drop, it rebounds back to the height of \"%282%2F3%29%2818%29=36%2F3=12\" feet. So it starts at 18 ft, drops to 0 ft, then bounces back to 12 ft\r
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\n" ); document.write( "\n" ); document.write( "Now after the second drop, it bounces back to a height of \"%282%2F3%29%2812%29=24%2F3=8\" ft. So the ball starts at 12 ft, goes to 0 ft, then back up to 8 ft\r
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\n" ); document.write( "\n" ); document.write( "Finally, after the third drop, the ball rebounds to a height of about \"%282%2F3%29%288%29=16%2F3=5.333\" (note: this is approximate) feet. So it starts at 8 ft, drops to 0 ft, and then back up to roughly 5.333 ft\r
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\n" ); document.write( "\n" ); document.write( "So the answer is 5.333 ft\r
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\n" ); document.write( "\n" ); document.write( "Notice how I took each previous answer and I multiplied it by \"2%2F3\". So on the first drop, I multiplied \"2%2F3\" by 18 to get the following (Let's call that result \"a\")\r
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\n" ); document.write( "\n" ); document.write( "So \"a=18%2A%282%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now I then multiplied that result by another \"2%2F3\" to get (now let's call it \"b\")\r
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\n" ); document.write( "\n" ); document.write( "\"b=a%2A%282%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"b=18%2A%282%2F3%29%2A%282%2F3%29\" Plug in \"a=18%2A%282%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Finally, I multiplied that previous result \"b\" by \"2%2F3\" to get the next height (which we'll call \"c\")\r
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\n" ); document.write( "\n" ); document.write( "\"c=b%2A%282%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"c=18%2A%282%2F3%29%2A%282%2F3%29%2A%282%2F3%29\" Plug in \"b=18%2A%282%2F3%29%2A%282%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "So after the third drop, there are 3 \"2%2F3\" terms. After the second drop, there are 2 \"2%2F3\" terms. After the first drop, there's only one \"2%2F3\" term.\r
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\n" ); document.write( "\n" ); document.write( "So this means that after \"x\" drops (where you can plug any positive number in for \"x\"), there will be \"x\" \"2%2F3\" terms after the initial \"18\". So the equation might look like this:\r
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\n" ); document.write( "\n" ); document.write( "To make things look tidy, we can condense the \"x\" number of \"2%2F3\" terms to get \r
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\n" ); document.write( "\n" ); document.write( "\"h=18%282%2F3%29%5Ex\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation is \"h=18%282%2F3%29%5Ex\" where \"h\" is the height and \"x\" is the number of drops.\r
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\n" ); document.write( "\n" ); document.write( "Notice how if we let \"x=3\", then \r
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\n" ); document.write( "\n" ); document.write( "\"h=18%282%2F3%29%5E%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"h=18%288%2F9%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"h=2%288%2F3%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"h=16%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"h=5.333\"\r
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\n" ); document.write( "\n" ); document.write( "which was our original answer.\r
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