document.write( "Question 177400: Last one...
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document.write( "3 dice are tossed - what is probability a) only two 5s b) at least two 5s c)three 5s d) no 5s\r
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document.write( "1 five - 1 dice = 1/5 right? what's next? \n" );
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Algebra.Com's Answer #132447 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 3 dice are tossed - \r \n" ); document.write( "\n" ); document.write( "what is probability \n" ); document.write( "a) only two 5s \n" ); document.write( "The probability of getting a 5 with one die is 1/6 \n" ); document.write( "P(two 5's on three dice) = 3C2(1/6)^2*(5/6) = 3*(7/6^3) = 0.097222... \n" ); document.write( "------------------------------------\r \n" ); document.write( "\n" ); document.write( "b) at least two 5s \n" ); document.write( "P(at least 2) = P(2 5's) + P(3 5's) = 0.097222 + 3C3((1/6)^3 = 1*(1/216) \n" ); document.write( "= 0.9768... \n" ); document.write( "----------------------------------- \r \n" ); document.write( "\n" ); document.write( "c)three 5s \n" ); document.write( "P( 3 5's) = 1/6^3 = 1/216 = 0.0046296.. \n" ); document.write( "-----------------------\r \n" ); document.write( "\n" ); document.write( "d) no 5s \n" ); document.write( "P( no 5's) = (5/6)^3 = 0.5787037.. \n" ); document.write( "------------------------- \n" ); document.write( "1 five - 1 dice = 1/6 But one five on 3 dice is not 1/5, it is \n" ); document.write( "3C1(1/6)^1(5/6)^2 = 75/216 = 0.3472222 \n" ); document.write( "-------------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |