document.write( "Question 177343: This is a question in a Finance course I am tutoring, but it has me stumped.
\n" ); document.write( "If A=D+E and D/A= 0.70, solve for A/E. What am I missing? Thanks.
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Algebra.Com's Answer #132398 by Fombitz(32388)\"\" \"About 
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1.\"A=D%2BE\"
\n" ); document.write( "2.\"D%2FA=0.7\"
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\n" ); document.write( "From 2,
\n" ); document.write( "\"D=0.7%2AA\"
\n" ); document.write( "Plug that into 1,
\n" ); document.write( "1.\"A=D%2BE\"
\n" ); document.write( "\"A=0.7A%2BE\"
\n" ); document.write( "\"0.3A=E\"
\n" ); document.write( "Multiply both sides by 10,
\n" ); document.write( "\"3A=10E\"
\n" ); document.write( "\"A%2FE=10%2F3\"\r
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