document.write( "Question 177332: give equation for 2x on line graph \n" ); document.write( "
Algebra.Com's Answer #132389 by MathLover1(20849)\"\" \"About 
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Solved by pluggable solver: Graphing Linear Equations
In order to graph \"y=2%2Ax%2B0\" we only need to plug in two points to draw the line
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\n" ); document.write( " So lets plug in some points
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\n" ); document.write( " Plug in x=-4
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\n" ); document.write( " \"y=2%2A%28-4%29%2B0\"
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\n" ); document.write( " \"y=-8%2B0\" Multiply
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\n" ); document.write( " \"y=-8\" Add
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\n" ); document.write( " So here's one point (-4,-8)
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\n" ); document.write( " Now lets find another point
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\n" ); document.write( " Plug in x=-3
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\n" ); document.write( " \"y=2%2A%28-3%29%2B0\"
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\n" ); document.write( " \"y=-6%2B0\" Multiply
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\n" ); document.write( " \"y=-6\" Add
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\n" ); document.write( " So here's another point (-3,-6). Add this to our graph
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\n" ); document.write( " Now draw a line through these points
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\n" ); document.write( " So this is the graph of \"y=2%2Ax%2B0\" through the points (-4,-8) and (-3,-6)
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\n" ); document.write( " So from the graph we can see that the slope is \"2%2F1\" (which tells us that in order to go from point to point we have to start at one point and go up 2 units and to the right 1 units to get to the next point) the y-intercept is (0,\"0\")and the x-intercept is (\"0\",0)
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\n" ); document.write( " We could graph this equation another way. Since \"b=0\" this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,\"0\").
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\n" ); document.write( " So we have one point (0,\"0\")
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\n" ); document.write( " Now since the slope is \"2%2F1\", this means that in order to go from point to point we can use the slope to do so. So starting at (0,\"0\"), we can go up 2 units
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\n" ); document.write( " and to the right 1 units to get to our next point
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\n" ); document.write( " Now draw a line through those points to graph \"y=2%2Ax%2B0\"
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\n" ); document.write( " So this is the graph of \"y=2%2Ax%2B0\" through the points (0,0) and (1,2)
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