document.write( "Question 177320: need help with this problem 12-√(12²-4*84)/2\r
\n" ); document.write( "\n" ); document.write( "here is what i have so far...
\n" ); document.write( "12-√-192/2
\n" ); document.write( "

Algebra.Com's Answer #132385 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"x+=+%28-%28-12%29+%2B-+sqrt%28+%28-12%29%5E2-4%2A1%2A84+%29%29%2F%282%2A1%29+\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2812+%2B-+sqrt%28+-192+%29%29%2F2+\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "But you can't take the square root of a negative number, so use the fact that the imaginary number i is defined as \"i%5E2+=+-1\":\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2812+%2B-+sqrt%28+i%5E2%28192%29+%29%29%2F2+\" \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2812+%2B-+i%2Asqrt%28+192+%29%29%2F2+\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2812+%2B-+i%2Asqrt%28+64%2A3+%29%29%2F2+\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+%2812+%2B-+8i%2Asqrt%28+3+%29%29%2F2+\" \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x+=+6+%2B-+4i%2Asqrt%28+3+%29+\"
\n" ); document.write( "
\n" );