document.write( "Question 24810: The length of a rectangular is 10 feet more than twice its width. the perimeter of the rectangule is 170feet. find the dimension of the rectangle\r
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document.write( "please reply me the answer in detail steps. thanks! \n" );
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Algebra.Com's Answer #13238 by Paul(988) ![]() You can put this solution on YOUR website! Length = 10+2x \n" ); document.write( "width = x \n" ); document.write( "Formula = 2(l+w)=P\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(x+2x+10)=170 \n" ); document.write( "6x+20=170 \n" ); document.write( "6x=150 \n" ); document.write( "x = 25\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25(2)+10= 60\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence the length is 60ft and the width is 25ft. \n" ); document.write( "Paul. \n" ); document.write( " |