document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177293>Question 177293</A>: <I><SPAN STYLE=\"word-break: break-all;\"> perimeter of a rectangle is 78 m. The length is 9 m more than twice the width. Find the dimentions of the lenghth and width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132373 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L+2W=PERIMETER IS THE FORMULA.<BR>\n" );
document.write( "L=2W+9 THIS IS GIVEN<BR>\n" );
document.write( "2(2W+9)+2W=78<BR>\n" );
document.write( "4W+18+2W=78<BR>\n" );
document.write( "6W=78-18<BR>\n" );
document.write( "6W=60<BR>\n" );
document.write( "W=60/6<BR>\n" );
document.write( "W=10 m. ans. for the width.<BR>\n" );
document.write( "L=2*10+9<BR>\n" );
document.write( "l=20+9<BR>\n" );
document.write( "L=29 m. ans. for the length.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2*29+2*10=78<BR>\n" );
document.write( "58+20=78<BR>\n" );
document.write( "78=78<BR>\n" );
document.write( "  <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );