document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177288>Question 177288</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0078228948/algebrahomeworkh>Glencoe Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to help my son with the following problem regarding solving  compound inequalities: 5/x + 3 > 0.  I understand the steps involved and how to graph the equation.  I can get as far as 5/x > -3 but I don't know how to solve for x or get x on the side by itself.\r<BR>\n" );
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document.write( "Thank you for your help </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132368 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132368\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5/x + 3 > 0<BR>\n" );
document.write( "5/x > -3<BR>\n" );
document.write( "Multiply both sides by x:<BR>\n" );
document.write( "x(5/x) > x(-3)<BR>\n" );
document.write( "5 > -3x<BR>\n" );
document.write( "Finally, divide both sides by -3:<BR>\n" );
document.write( "-5/3 < x<BR>\n" );
document.write( "Read 'x' is greater than -5/3<BR>\n" );
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document.write( "Notice that the \"greater than\" symbol is now reversed as a \"less than\" symbol -- this is because we divided by a negative number.\r<BR>\n" );
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