document.write( "Question 177273: Please help me solve this equation:
\n" ); document.write( "1/6(3y-2)=1 -1/3(y-1)\r
\n" ); document.write( "\n" ); document.write( "This is what I have come up with:
\n" ); document.write( "1/2y -1/3 = 1 -1/3+1/3, then I multiplied both sides by GCF of 6 to give me:
\n" ); document.write( "3y -2 = 6 -2y+2, then combine like terms
\n" ); document.write( "3y -2 = 4 -2y,
\n" ); document.write( "5y = 6
\n" ); document.write( "y = 6/5\r
\n" ); document.write( "\n" ); document.write( "When I try and plug in my answer it doesn't check:
\n" ); document.write( "1/6(18/5 -2) = 1 -1/3(6/5 -1), multiply by GCF of 15,
\n" ); document.write( "15(3/5 -1/3) = (1 -6/15 + 1/3)15
\n" ); document.write( "9 -5 = 15 -6 +5 Does not check\r
\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Betty \n" ); document.write( "
Algebra.Com's Answer #132346 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(1/6)(3y-2) = 1 - (1/3)(y-1)
\n" ); document.write( "-----------
\n" ); document.write( "Multiply thru by 6 to get:
\n" ); document.write( "(3y-2) = 6 - 2(y-1)
\n" ); document.write( "3y-2 = 6 - 2y + 2
\n" ); document.write( "5y = 10
\n" ); document.write( "y = 2
\n" ); document.write( "=========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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