document.write( "Question 177262This question is from textbook college algebras
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\n" ); document.write( "Thank you in advance for helping me set this up and compute the answer.
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Algebra.Com's Answer #132336 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"A=P%281%2Br%2Fn%29%5E%28nt%29\" Start with the compound interest formula where A is the return, P is the principal (the amount invested), r is the interest rate, n is the compound frequency, and t is the time (in years)\r
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\n" ); document.write( "\n" ); document.write( "\"350=200%281%2Br%2F1%29%5E%281%2A5%29\" Plug in \"A=350\", \"p=200\", \"n=1\", and \"t=5\"\r
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\n" ); document.write( "\n" ); document.write( "\"350=200%281%2Br%2F1%29%5E5\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"350=200%281%2Br%29%5E5\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"350%2F200=%281%2Br%29%5E5\" Divide both sides by 200.\r
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\n" ); document.write( "\n" ); document.write( "\"1.75=%281%2Br%29%5E5\" Divide.\r
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\n" ); document.write( "\n" ); document.write( "\"root%285%2C1.75%29=1%2Br\" Take the 5th root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"1.1184=1%2Br\" Take the 5th root of 1.75 to get 1.118 (this is approximate)\r
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\n" ); document.write( "\n" ); document.write( "\"1.1184-1=r\" Subtract 1 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"0.1184=r\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"r=0.1184\" which is roughly 11.84%\r
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\n" ); document.write( "\n" ); document.write( "So the interest rate needed is about 11.84%
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