document.write( "Question 177238This question is from textbook
\n" ); document.write( ": Solve and check. Begin by rewriting the equation without the fraction.
\n" ); document.write( "2x/3-5=7. I have no idea how to change the fraction 2x/3 and then to solve the equation. After solving it how do I put the answer back in to check it?
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Algebra.Com's Answer #132327 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"2x%2F3-5=7\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%282x%2Fcross%283%29%29-3%285%29=3%287%29\" Multiply EVERY term by the LCD \"3\" to clear the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"2x-15=21\" Multiply and simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=21%2B15\" Add \"15\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2x=36\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2836%29%2F%282%29\" Divide both sides by \"2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=18\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=18\"
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