document.write( "Question 177243: i'm suppose to factor completely and can you please show the steps, thank you\r
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\n" ); document.write( "\n" ); document.write( "61) 12x3 + 16x2 – 400x
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\n" ); document.write( "62) x3 + 3x2 + 2x + 6
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\n" ); document.write( "63) x2 – 3x + 2
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Algebra.Com's Answer #132319 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 61\r
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\n" ); document.write( "\n" ); document.write( "\"12x%5E3%2B16x%5E2-400x\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"4x%283x%5E2%2B4x-100%29\" Factor out the GCF \"4x\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's try to factor the inner expression \"3x%5E2%2B4x-100\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at \"3x%5E2%2B4x-100\" we can see that the first term is \"3x%5E2\" and the last term is \"-100\" where the coefficients are 3 and -100 respectively.\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient 3 and the last coefficient -100 to get -300. Now what two numbers multiply to -300 and add to the middle coefficient 4? Let's list all of the factors of -300:\r
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\n" ); document.write( "\n" ); document.write( "Factors of -300:\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,5,6,10,12,15,20,25,30,50,60,75,100,150,300\r
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\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-5,-6,-10,-12,-15,-20,-25,-30,-50,-60,-75,-100,-150,-300 ...List the negative factors as well. This will allow us to find all possible combinations\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to -300\r
\n" ); document.write( "\n" ); document.write( "(1)*(-300)\r
\n" ); document.write( "\n" ); document.write( "(2)*(-150)\r
\n" ); document.write( "\n" ); document.write( "(3)*(-100)\r
\n" ); document.write( "\n" ); document.write( "(4)*(-75)\r
\n" ); document.write( "\n" ); document.write( "(5)*(-60)\r
\n" ); document.write( "\n" ); document.write( "(6)*(-50)\r
\n" ); document.write( "\n" ); document.write( "(10)*(-30)\r
\n" ); document.write( "\n" ); document.write( "(12)*(-25)\r
\n" ); document.write( "\n" ); document.write( "(15)*(-20)\r
\n" ); document.write( "\n" ); document.write( "(-1)*(300)\r
\n" ); document.write( "\n" ); document.write( "(-2)*(150)\r
\n" ); document.write( "\n" ); document.write( "(-3)*(100)\r
\n" ); document.write( "\n" ); document.write( "(-4)*(75)\r
\n" ); document.write( "\n" ); document.write( "(-5)*(60)\r
\n" ); document.write( "\n" ); document.write( "(-6)*(50)\r
\n" ); document.write( "\n" ); document.write( "(-10)*(30)\r
\n" ); document.write( "\n" ); document.write( "(-12)*(25)\r
\n" ); document.write( "\n" ); document.write( "(-15)*(20)\r
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\n" ); document.write( "\n" ); document.write( "note: remember, the product of a negative and a positive number is a negative number\r
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\n" ); document.write( "\n" ); document.write( "Now which of these pairs add to 4? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 4\r
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First NumberSecond NumberSum
1-3001+(-300)=-299
2-1502+(-150)=-148
3-1003+(-100)=-97
4-754+(-75)=-71
5-605+(-60)=-55
6-506+(-50)=-44
10-3010+(-30)=-20
12-2512+(-25)=-13
15-2015+(-20)=-5
-1300-1+300=299
-2150-2+150=148
-3100-3+100=97
-475-4+75=71
-560-5+60=55
-650-6+50=44
-1030-10+30=20
-1225-12+25=13
-1520-15+20=5
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\n" ); document.write( "\n" ); document.write( "None of these pairs of factors add to 4. So the expression \"3x%5E2%2B4x-100\" cannot be factored\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "So \"12x%5E3%2B16x%5E2-400x\" factors to \"4x%283x%5E2%2B4x-100%29\"\r
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\n" ); document.write( "\n" ); document.write( "# 62\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3%2B3x%5E2%2B2x%2B6\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E3%2B3x%5E2%29%2B%282x%2B6%29\" Group like terms\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%28x%2B3%29%2B2%28x%2B3%29\" Factor out the GCF \"x%5E2\" out of the first group. Factor out the GCF \"2\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B2%29%28x%2B3%29\" Since we have the common term \"x%2B3\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E3%2B3x%5E2%2B2x%2B6\" factors to \"%28x%5E2%2B2%29%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E3%2B3x%5E2%2B2x%2B6=%28x%5E2%2B2%29%28x%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "# 63\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"x%5E2-3x%2B2\", we can see that the first coefficient is \"1\", the second coefficient is \"-3\", and the last term is \"2\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"1\" by the last term \"2\" to get \"%281%29%282%29=2\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"2\" (the previous product) and add to the second coefficient \"-3\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"2\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"2\":\r
\n" ); document.write( "\n" ); document.write( "1,2\r
\n" ); document.write( "\n" ); document.write( "-1,-2\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"2\".\r
\n" ); document.write( "\n" ); document.write( "1*2
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-3\":\r
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First NumberSecond NumberSum
121+2=3
-1-2-1+(-2)=-3
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-1\" and \"-2\" add to \"-3\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-1\" and \"-2\" both multiply to \"2\" and add to \"-3\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-3x\" with \"-x-2x\". Remember, \"-1\" and \"-2\" add to \"-3\". So this shows us that \"-x-2x=-3x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bhighlight%28-x-2x%29%2B2\" Replace the second term \"-3x\" with \"-x-2x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-x%29%2B%28-2x%2B2%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-1%29%2B%28-2x%2B2%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-1%29-2%28x-1%29\" Factor out \"2\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-2%29%28x-1%29\" Combine like terms. Or factor out the common term \"x-1\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2-3x%2B2\" factors to \"%28x-2%29%28x-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"x%5E2-3x%2B2=%28x-2%29%28x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by FOILing \"%28x-2%29%28x-1%29\" to get \"x%5E2-3x%2B2\" or by graphing the original expression and the answer (the two graphs should be identical).
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