document.write( "Question 177240This question is from textbook
\n" ); document.write( ": Use properties of equality to isolate x on one side of the equation and the small figures on the other side.
\n" ); document.write( "The problem: If x/5-2=x/3, evaluate x squared -2. x/5 is x over 5 and x/3 is x over 3. I have no idea. Please help!
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Algebra.Com's Answer #132318 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, solve for \"x\":\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F5-2=x%2F3\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"15%28x%2Fcross%285%29%29-15%282%29=15%28x%2Fcross%283%29%29\" Multiply EVERY term by the LCD \"15\" to clear the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"3x-30=5x\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=5x%2B30\" Add \"30\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x-5x=30\" Subtract \"5x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-2x=30\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%2830%29%2F%28-2%29\" Divide both sides by \"-2\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=-15\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Now that we found \"x\", we can evaluate \"x%5E2-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-2\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%28-15%29%5E2-2\" Plug in \"x=-15\" \r
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\n" ); document.write( "\n" ); document.write( "\"225-2\" Square -15 to get 225\r
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\n" ); document.write( "\n" ); document.write( "\"223\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "So \"x%5E2-2=223\" when \"x=-15\"
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