document.write( "Question 177235: Ziggy’s Famous Yogurt blends regular yogurt that is 3% fat with its no-fat yogurt to obtain lowfat yogurt that is 1% fat. How many pounds of regular
\n" ); document.write( "yogurt and how many pounds of no-fat yogurt should be mixed to obtain 60 pounds of low-fat yogurt? \n" ); document.write( "
Algebra.Com's Answer #132314 by gonzo(654)\"\" \"About 
You can put this solution on YOUR website!
let x = pounds of regular yogurt (3% fat)
\n" ); document.write( "let y = pounds of no fat yogurt (0% fat)
\n" ); document.write( "60 = pounts of low fat yogurt (1% fat)
\n" ); document.write( "you have two simultaneous equations that need top be solved.
\n" ); document.write( "they are:
\n" ); document.write( ".03 * x + .00 * y = .01 * 60
\n" ); document.write( "x + y = 60
\n" ); document.write( "from the second formula, you can determine that:
\n" ); document.write( "y = 60 - x
\n" ); document.write( "the second formula is:
\n" ); document.write( ".03 * x + .00 * y = .01 * 60
\n" ); document.write( "which becomes:
\n" ); document.write( ".03 * x = .01 * 60 because the y cancels out.
\n" ); document.write( "divide both sides by .03 to get:
\n" ); document.write( "x = (.01*60)/.03 = 20
\n" ); document.write( "looks like you need 20 pounds of regular yogurt.
\n" ); document.write( "since y = 60 - x, the amount of no fat yogurt required is 40 pounds.
\n" ); document.write( "to prove, substitute in the original equation.
\n" ); document.write( ".03 * 20 + .00 * 40 = .03 * 60
\n" ); document.write( "this becomes:
\n" ); document.write( ".6 = .6
\n" ); document.write( "equation is true.
\n" ); document.write( "value of 20 pounds of regular yogurt mixed with 40 pounds of no fat yogurt is good.
\n" ); document.write( "your answer is:
\n" ); document.write( "20 pounds of regular yogurt needs to be mixed with 40 pounds of no fat yogurt to get 60 pounds of low fat yogurt. \n" ); document.write( "
\n" );