document.write( "Question 177206: If (log_9)4=a and (log_27)5=b, find and expression in terms of a and b for log_(square root over 3)40 \n" ); document.write( "
Algebra.Com's Answer #132287 by stanbon(75887)\"\" \"About 
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If (log_9)4=a
\n" ); document.write( "So 9^a = 4
\n" ); document.write( "Therefore (sqrt(3))^(4a) = 4
\n" ); document.write( "And log(sqrt(3)4 = 4a
\n" ); document.write( "Also log(sqrt(3)2 = 2a
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\n" ); document.write( "and (log_27)5=b
\n" ); document.write( "So 27^b = 5
\n" ); document.write( "Therefore (sqrt(3))^(6b) = 5
\n" ); document.write( "And log(sqrt(3)5 = 6b
\n" ); document.write( "-----------------------------------\r
\n" ); document.write( "\n" ); document.write( "find and expression in terms of a and b for log_(square root over 3)40
\n" ); document.write( "log(sqrt(3))40 = log(sqrt(3)[2*4*5]
\n" ); document.write( "log(sqrt(3))2 + log(sqrt(3)4 + log(sqrt(3)5
\n" ); document.write( "= 2a + 4a + 6b
\n" ); document.write( "= 6(a+b)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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