document.write( "Question 177035: Solve equations
\n" ); document.write( "x/3 = 4/x+1\r
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\n" ); document.write( "\n" ); document.write( "-3/x = x/-3
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Algebra.Com's Answer #132282 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
x/3 = 4/x+1
\n" ); document.write( "Multiply both sides by 3x:
\n" ); document.write( "x^2 = 12+3x
\n" ); document.write( "Move all terms to the left:
\n" ); document.write( "x^2-3x-12=0
\n" ); document.write( "Since you can't factor, you must apply the quadratic equation. Doing so, yields:
\n" ); document.write( "x={5.2749, -2.2749}
\n" ); document.write( "Here's the details of the quadratic:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-3x%2B-12+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-3%29%5E2-4%2A1%2A-12=57\".
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\n" ); document.write( " Discriminant d=57 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--3%2B-sqrt%28+57+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-3%29%2Bsqrt%28+57+%29%29%2F2%5C1+=+5.27491721763537\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-3%29-sqrt%28+57+%29%29%2F2%5C1+=+-2.27491721763537\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-3x%2B-12\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-3x%2B-12+=+1%28x-5.27491721763537%29%2A%28x--2.27491721763537%29\"
\n" ); document.write( " Again, the answer is: 5.27491721763537, -2.27491721763537.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-3%2Ax%2B-12+%29\"

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\n" ); document.write( "-3/x = x/-3
\n" ); document.write( "Multiply both sides by -3x:
\n" ); document.write( "9 = x^2
\n" ); document.write( "Taking the square root of both sides:
\n" ); document.write( "x = {-3,3}
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