document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177177>Question 177177</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A total of 285 tickets were sold for the school play. The number of student tickets sold was two times the number of adult tickets sold . How many adult tickets were sold?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132234 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132234\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let S = the number of student tickets sold and A = the number of adult tickets sold.<BR>\n" );
document.write( "From the problem, you can write:<BR>\n" );
document.write( "1) S+A = 285 \"A total of 285 (student plus adult) tickets were sold...\"<BR>\n" );
document.write( "2) S = 2A \"The number of student tickets (S) sold was two times the number of adult tickets (A) sold.\"<BR>\n" );
document.write( "Substitute equation 2) (S = 2A) for S in equation 1).<BR>\n" );
document.write( "(2A+A) = 285 Simplify.<BR>\n" );
document.write( "3A = 285 Divide both sides by 3.<BR>\n" );
document.write( "A = 95 This is the number of adult tickets sold.<BR>\n" );
document.write( "From equation 2)...<BR>\n" );
document.write( "S = 2A<BR>\n" );
document.write( "S = 2(95)<BR>\n" );
document.write( "S = 190 This is the number of student tickets sold. </SPAN>\n" );
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