document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177185>Question 177185</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice its width. If the perimeter of the rectangle is 30ft, find its area </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132227 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132227\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is twice its width. If the perimeter of the rectangle is 30ft, find its area<BR>\n" );
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document.write( "Perimeter = 2(L+W) = 30<BR>\n" );
document.write( "L + W= 15<BR>\n" );
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document.write( "But L = 2W, so substitute to get:<BR>\n" );
document.write( "2W + W = 15<BR>\n" );
document.write( "3W = 15<BR>\n" );
document.write( "W = 5<BR>\n" );
document.write( "L = 2W = 10<BR>\n" );
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document.write( "Area = LW = 10*5 = 50 sq. ft.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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