document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24771>Question 24771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I made up this problem, but I don't know how to solve it. It looks easy, but I get frustrated. \r<BR>\n" );
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document.write( "4^-95*4^100  {4 to the power of negative 95 times 4 to the power of 100} </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13222 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13222\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiply 2 terms together, their powers add.\r<BR>\n" );
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document.write( "So -95+100 is 5\r<BR>\n" );
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document.write( "So answer is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4%5E5 ALIGN=MIDDLE  ALT=\"4%5E5\"   DISABLED_style= \"max-width:90%; height:auto;\" > which is 1024\r<BR>\n" );
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document.write( "jon. </SPAN>\n" );
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