document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177142>Question 177142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thank you very much for the answer<BR>\n" );
document.write( "Now i have another question<BR>\n" );
document.write( " can you explain me the process of how this ended up given                 (25/28)d + 9 = d\r<BR>\n" );
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document.write( "I have the following<BR>\n" );
document.write( "d/6+d/12+d/7+5+d/2+4=d I do get where the 9 comes from, but i tried to add that up by using LCD and it did not give 25/28.\r<BR>\n" );
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document.write( "Please can you explain me the process...<BR>\n" );
document.write( "Thanks as always </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132215 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132215\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d/6+d/12+d/7+5+d/2+4=d   LCM is 84, so<BR>\n" );
document.write( "14d/84  + 7d/84 + 12d/84 + 5 +42d/84 + 4 =d simplifying<BR>\n" );
document.write( "75d/84 + 5 + 4=d<BR>\n" );
document.write( "(25/28)d+9=d subtract (25/28)d from each side<BR>\n" );
document.write( "9=(28/28)d-(25/28)d or<BR>\n" );
document.write( "(3/28)d=9<BR>\n" );
document.write( "d=(9*28)/3=84\r<BR>\n" );
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document.write( "Does this help???---------------ptaylor </SPAN>\n" );
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