document.write( "Question 177161: Find two numbers whose sum is 39 and such that one is 2 times as large as the other. (We will call the two numbers x and y.) \n" ); document.write( "

Algebra.Com's Answer #132208 by ptaylor(2198) $\"\"$ $\"About$

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\n" ); document.write( "Let x=one number
\n" ); document.write( "Then 39-x=the other number
\n" ); document.write( "Now we are told that one number (lets say x) is 2 times as large as the other, so our equatin to solve is:\r
\n" ); document.write( "\n" ); document.write( "x=2(39-x) get rid of parens
\n" ); document.write( "x=78-2x add 2x to each side
\n" ); document.write( "x+2x=78-2x+2x collect like terms
\n" ); document.write( "3x=78 divide each side by 3
\n" ); document.write( "x=26---------------------------one number \r
\n" ); document.write( "\n" ); document.write( "39-x=39-26=13---------------the other number\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "OK now we will call the two numbers x and y
\n" ); document.write( "x+y=39-------------------eq1
\n" ); document.write( "and
\n" ); document.write( "y=2x----------------eq2
\n" ); document.write( "substitute y=2x into eq1
\n" ); document.write( "x+2x=39
\n" ); document.write( "3x=39
\n" ); document.write( "x=13 one number
\n" ); document.write( "y=2x=2*13=26 the other number\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Does this help???-------------ptaylor \n" ); document.write( "

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