document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24770>Question 24770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Having trouble with this one. This is as far as I got in solving this literal equation:<BR>\n" );
document.write( "Solve:S=2wh+2wl+2lh,solve for h<BR>\n" );
document.write( "S-2wh-2wl=2lh\r<BR>\n" );
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document.write( "but then I got confused because the answer is h= s-2wl/2w+2l\r<BR>\n" );
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document.write( "Can you please help me figure out how they got to this answer?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13218 by </B><A HREF=/tutors/aboutme.mpl?userid=daleswift><B>daleswift(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=daleswift><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)  S = 2wh + 2wl + 2lh\r<BR>\n" );
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document.write( "2)  S - 2wl = 2wh + 2lh\r<BR>\n" );
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document.write( "3)  S - 2wl = 2h (w + l)\r<BR>\n" );
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document.write( "4)  (S -2wl)/(w+1) = 2h\r<BR>\n" );
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document.write( "5)  (S - 2wl) / 2(w+1) = h   </SPAN>\n" );
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