document.write( "Question 24770: Having trouble with this one. This is as far as I got in solving this literal equation:
\n" ); document.write( "Solve:S=2wh+2wl+2lh,solve for h
\n" ); document.write( "S-2wh-2wl=2lh\r
\n" ); document.write( "\n" ); document.write( "but then I got confused because the answer is h= s-2wl/2w+2l\r
\n" ); document.write( "\n" ); document.write( "Can you please help me figure out how they got to this answer?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #13217 by longjonsilver(2297) $\"\"$ $\"About$

You can put this solution on YOUR website!
you need all the terms with h in on one side and all the other terms on the other side. So,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "S=2wh+2wl+2lh
\n" ); document.write( "s - 2wh - 2lh = 2wl
\n" ); document.write( "-2wh - 2lh = 2wl - s\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "converting all signs gives 2wh + 2lh = s - 2wl\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now factorise, to give h(2w + 2l) = s - 2wl\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "And final answer is: $\"h+=+%28s+-+2wl%29%2F%282w+%2B+2l%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "jon.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );