document.write( "Question 177067: if the two sidea of a rectangle change so the new area is double the original area,and one side is increased by 50%,what percentage increase or decrease of the other side???? \n" ); document.write( "
Algebra.Com's Answer #132162 by HyperBrain(694)![]() ![]() ![]() You can put this solution on YOUR website! Let A=area of the original rectangle \n" ); document.write( "x=length of the orig. rectangle \n" ); document.write( "y=width of the orig. rectangle\r \n" ); document.write( "\n" ); document.write( "Then \n" ); document.write( "A=x*y\r \n" ); document.write( "\n" ); document.write( "If the new area is double the orig. rectangle\r \n" ); document.write( "\n" ); document.write( "Then\r \n" ); document.write( "\n" ); document.write( "2*x*y=area of the new rectangle\r \n" ); document.write( "\n" ); document.write( "if you increase one side (let's say the length) by 50%, you are adding x/2 \n" ); document.write( "so the new length is x+(x/2)=3x/2\r \n" ); document.write( "\n" ); document.write( "Let W=new width\r \n" ); document.write( "\n" ); document.write( "Then\r \n" ); document.write( "\n" ); document.write( "2*x*y=(3x/2)W \n" ); document.write( "4*x*y=3xW multiply by 2 both sides \n" ); document.write( "4y=3W divide both sides by x \n" ); document.write( "W=4y/3=y +(y/3)\r \n" ); document.write( "\n" ); document.write( "1/3 is 33 1/3%. \n" ); document.write( "Therefore, the width is increased by 33 1/3%.\r \n" ); document.write( "\n" ); document.write( "Power up, \n" ); document.write( "HyperBrain!\r \n" ); document.write( "\n" ); document.write( "Help us promote our advocacy no straws, no plastics, no styros. \n" ); document.write( "Visit these sites: \n" ); document.write( "http://uselessplastic.wordpress.com \n" ); document.write( "http://uselessplastic.multiply.com \n" ); document.write( " |