document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177069>Question 177069</A>: <I><SPAN STYLE=\"word-break: break-all;\">  3/[SQRT(5) - 2] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132157 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/[SQRT(5) - 2]<BR>\n" );
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document.write( "To rationalize the denominator multiply numerator and denominator<BR>\n" );
document.write( "by the conjugate of sqrt(5)-2 which is sqrt(5)+2<BR>\n" );
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document.write( "= [3(sqrt(5)+2]/[5-4]\r<BR>\n" );
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document.write( "= 3sqrt(5) + 6<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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