document.write( "Question 177097This question is from textbook
\n" ); document.write( ": Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #132153 by stanbon(75887)\"\" \"About 
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Mike invested $6000 for one year. He invested part of it at 9% and the rest at 11%. At the end of the year he earned $624 in interest. How much did he invest at each rate?
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\n" ); document.write( "Equation:
\n" ); document.write( "interest + interest = interest
\n" ); document.write( "0.09x + 0.11(6000-x) = 624\r
\n" ); document.write( "\n" ); document.write( "9x + 11(6000-x) = 62400\r
\n" ); document.write( "\n" ); document.write( "9x + 66000 - 9x = 62400
\n" ); document.write( "-2x = - 3600
\n" ); document.write( "x = $1800 (amt. invested at 9%)
\n" ); document.write( "6000-x = $4200 (amt. invested at 11%)
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\n" ); document.write( "Cheers
\n" ); document.write( "Stan H.
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