document.write( "Question 177065: A bag contains a red, a blue, a yellow, a white, and a green ball. Three balls are drawn out without replacement. \r
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Algebra.Com's Answer #132150 by scott8148(6628)\"\" \"About 
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a) the number of possible triplets (3) from a group of five is 5C3 (order is NOT important)\r
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\n" ); document.write( "\n" ); document.write( "5C3 = 5! / (3! * 2!) = 120 / (6 * 2) = 10\r
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\n" ); document.write( "\n" ); document.write( "the red and yellow can be combined with any of the 3 other colors, so there are 3 triplets containing red & yellow\r
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\n" ); document.write( "\n" ); document.write( "the probability of red & yellow is 3 in 10 or .3\r
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\n" ); document.write( "\n" ); document.write( "b) the number of triplets from a group of 5 if order IS important is 5P3\r
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\n" ); document.write( "\n" ); document.write( "5P3 = 5! / 2! = 120 / 2 = 60\r
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\n" ); document.write( "\n" ); document.write( "again, the red & yellow can be combined with each of the other 3 colors
\n" ); document.write( "__ but each of the resulting 3 triplets can be arranged in 6 ways (3 * 2 * 1)\r
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\n" ); document.write( "\n" ); document.write( "of the 6 ways, only 2 have the red & yellow in the proper order; either preceded by or followed by the 3rd color\r
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\n" ); document.write( "\n" ); document.write( "this means that 6 out of the 60 possible triplets have red & yellow in the proper order\r
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\n" ); document.write( "\n" ); document.write( "6 in 60 is a probability of .1
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