document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=177083>Question 177083</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jim's nephew owns a triangular plot of land. The perimeter fence that surounds the land measures 121 feet.  The shortest side is 15 feet longer than one half of the longest side.  The second longest side is 4 feet shorter than the longest side.  What is the length of each side. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132120 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132120\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the longest side   =   l<BR>\n" );
document.write( "Then shortest side   =   15   +   .5l<BR>\n" );
document.write( "And, second longest side =   l   -   4\r<BR>\n" );
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document.write( "Since the perimeter is 121,” then l  +  15  +  .5l  +  l  -  4  =  121\r<BR>\n" );
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document.write( "2.5l  =  110<BR>\n" );
document.write( "l  =  44\r<BR>\n" );
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document.write( "Therefore, longest side  =  44 feet<BR>\n" );
document.write( "Second longest  =  44  -   4  =  40 feet<BR>\n" );
document.write( "Shortest side  =  15  +  .5(44)  =  37 feet<BR>\n" );
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