document.write( "Question 176999: Find the domain and range of this function f(x)=1/squareroot of (x-4)\r
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Algebra.Com's Answer #132055 by rapaljer(4671) $\"\"$ $\"About$

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DOMAIN:\r
\n" ); document.write( "\n" ); document.write( "Domain is the set of all permissible x values. Since there is a square root in a denominator, the denominator can't equal 0, and the radicand cannot be negative. Therefore x-4>0, so x>4.\r
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\n" ); document.write( "\n" ); document.write( "RANGE:
\n" ); document.write( "Since $\"f%28x%29=1%2Fsqrt%28x-4%29\"$ there is a built-in restriction that f(x) cannot be negative or zero, since it's value is determined by the $\"sqrt%28x-4%29\"$ . Moreover, as x gets closer and closer to 4, the value of f(x) gets larger and larger, approaching infinity. \r
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\n" ); document.write( "\n" ); document.write( "Final answer in interval notation:\r
\n" ); document.write( "\n" ); document.write( "D: x>4 (4,inf)
\n" ); document.write( "R: y>0 (0, inf)\r
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\n" ); document.write( "\n" ); document.write( "R^2 \n" ); document.write( "

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