document.write( "Question 176999: Find the domain and range of this function f(x)=1/squareroot of (x-4)\r
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Algebra.Com's Answer #132053 by Fombitz(32388)\"\" \"About 
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The domain is all of the x values that make f(x) defined.
\n" ); document.write( "There are two restrictions on the domain to be concerned about.
\n" ); document.write( "First, the square root can only have zero or positive values as arguments, because the square root of a negative number is undefined.
\n" ); document.write( "\"x-4%3C0\"
\n" ); document.write( "\"x%3C4\"
\n" ); document.write( "Second, since it's a fraction, the denominator cannot be zero because division by zero is undefined.
\n" ); document.write( "Find the point(s) where the denominator equals zero.
\n" ); document.write( "\"x-4=0\"
\n" ); document.write( "\"x=4\"
\n" ); document.write( "If we put the two together, x cannot be less than 4 and x cannot be equal to 4.
\n" ); document.write( "Therefore the domain is x such that x is greater than 4.
\n" ); document.write( "Domain:(\"4\",\"infinity\")
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\n" ); document.write( "To get the range look at the domain.
\n" ); document.write( "Near x gets close to 4 (say 4.001), the denominator gets very small, the value of f(x) gets zero large.
\n" ); document.write( "As x gets very larger, the denominator gets very large, the value of f(x) goes towards 0.
\n" ); document.write( "Range:(\"0\",\"infinity\")
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