document.write( "Question 24750: 3) Suppose you throw a baseball straight up at a velocity of 64 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t2 + v0t + s0
\n" ); document.write( "• 16 represents 1/2g, the gravitational pull due to gravity (measured in feet per second2).
\n" ); document.write( "• v0 is the initial velocity (how hard do you throw the object, measured in feet per second).
\n" ); document.write( "• s0 is the initial distance above ground (in feet). If you are standing on the ground, then s0 = 0.
\n" ); document.write( "a) What is the function that describes this problem?
\n" ); document.write( "b) The ball will be how high above the ground after 1 second?
\n" ); document.write( "c) How long will it take to hit the ground? What is the maximum height of the ball? What time will the maximum height be attained?
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Algebra.Com's Answer #13205 by rapaljer(4671)\"\" \"About 
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a) s(t) = -16t^2 + 64t \r
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\n" ); document.write( "\n" ); document.write( "b) s(1) = -16(1)^2 + 64(1) = 48 feet\r
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\n" ); document.write( "\n" ); document.write( "c) s(t) = 0 at ground level, so
\n" ); document.write( "-16t^2 + 64 t= 0\r
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\n" ); document.write( "\n" ); document.write( "Solve by factoring the common factor of -16t:
\n" ); document.write( "-16t ( t - 4) = 0
\n" ); document.write( "t= 0 or t= 4\r
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\n" ); document.write( "\n" ); document.write( "Time to reach the ground is from t= 0 to t=4 which is 4 seconds.\r
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\n" ); document.write( "\n" ); document.write( "Maximum height will be halfway between t=0 and t=4, which is t= 2 seconds to reach the maximum height. Maximum height will be
\n" ); document.write( "s(t) = -16t^2 + 64 t
\n" ); document.write( "s(2) = -16(2)^2 + 64(2)
\n" ); document.write( "s(2) = -64 + 128 = 64 feet\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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