document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176985>Question 176985</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the length of a rectangle is increased by 120%and its width is decreased by 20%,what is the resulting percentage increase or decrease in the area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132047 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the length of a rectangle is increased by 120%and its width is decreased by 20%,what is the resulting percentage increase or decrease in the area?<BR>\n" );
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document.write( "Let x = width of original rectangle<BR>\n" );
document.write( "and y = length of original rectangle<BR>\n" );
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document.write( "\"original area\" = xy<BR>\n" );
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document.write( "New dimensions:<BR>\n" );
document.write( "x-.20x = .80x = width of new rectangle<BR>\n" );
document.write( "y+1.20y = 2.20y = length of new rectangle<BR>\n" );
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document.write( "\"new area\" = (.80x)(2.20y) = 1.76xy<BR>\n" );
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document.write( "Therefore, the percentage increase is 176% </SPAN>\n" );
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