document.write( "Question 176994: The path of a falling object is given by the function s=-16t^+v0t+s0 where the v0 represents the initial velocity in ft/sec ans s0represents the initial height. The variable t is time in seconds, and s is the height of the object in feet. if a rock is thrown upward with the initial velocity of 32 feet per secound from the top of a 40 foot building a) write the height equation b)how high is the rock after 5.0 seconds,after how many seconds will the rock reach maximum height and what is the height? \r
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Algebra.Com's Answer #132037 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a)\r
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\n" ); document.write( "\n" ); document.write( "Since the \"initial velocity of 32 feet per secound from the top of a 40 foot building\", this means that \"v%5B0%5D=32\" and \"s%5B0%5D=40\"\r
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\n" ); document.write( "\n" ); document.write( "So the equation is \"s=-16t%5E2%2B32t%2B40\" (after plugging in the initial velocity and position)\r
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\n" ); document.write( "\n" ); document.write( "b)\r
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\n" ); document.write( "\n" ); document.write( "\"how high is the rock after 5.0 seconds?\"\r
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\n" ); document.write( "\n" ); document.write( "Are you sure that the \"5\" isn't \"0.5\"? After 5 seconds, the rock wouldn't be in the air.\r
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\n" ); document.write( "\n" ); document.write( "\"s=-16t%5E2%2B32t%2B40\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"s=-16%280.5%29%5E2%2B32%280.5%29%2B40\" Plug in \"t=0.5\".\r
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\n" ); document.write( "\n" ); document.write( "\"s=-16%280.25%29%2B32%280.5%29%2B40\" Square \"0.5\" to get \"0.25\".\r
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\n" ); document.write( "\n" ); document.write( "\"s=-4%2B32%280.5%29%2B40\" Multiply \"-16\" and \"0.25\" to get \"-4\".\r
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\n" ); document.write( "\n" ); document.write( "\"s=-4%2B16%2B40\" Multiply \"32\" and \"0.5\" to get \"16\".\r
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\n" ); document.write( "\n" ); document.write( "\"s=52\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So after 0.5 seconds (half a second), the object is 52 ft in the air.\r
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\n" ); document.write( "\n" ); document.write( "c)\r
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\n" ); document.write( "\n" ); document.write( "\"after how many seconds will the rock reach maximum height\"\r
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\n" ); document.write( "\n" ); document.write( "To find the time where the object reaches the max height, we need to find the x-coordinate vertex of \"s=-16t%5E2%2B32t%2B40\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=%28-b%29%2F%282a%29\" Start with the vertex formula.\r
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\n" ); document.write( "\n" ); document.write( "From \"s=-16t%5E2%2B32t%2B40\", we can see that \"a=-16\", \"b=32\", and \"c=40\".\r
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\n" ); document.write( "\n" ); document.write( "\"t=%28-%2832%29%29%2F%282%28-16%29%29\" Plug in \"a=-16\" and \"b=32\".\r
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\n" ); document.write( "\n" ); document.write( "\"t=%28-32%29%2F%28-32%29\" Multiply 2 and \"-16\" to get \"-32\".\r
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\n" ); document.write( "\n" ); document.write( "\"t=1\" Divide.\r
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\n" ); document.write( "\n" ); document.write( "So at one second, the object will reach the max height.\r
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\n" ); document.write( "\n" ); document.write( "d)\r
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\n" ); document.write( "\n" ); document.write( "\"what is the (max) height?\"\r
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\n" ); document.write( "\n" ); document.write( "\"s=-16t%5E2%2B32t%2B40\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"s=-16%281%29%5E2%2B32%281%29%2B40\" Plug in \"t=1\" (the time at which the object will reach the peak).\r
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\n" ); document.write( "\n" ); document.write( "\"s=-16%281%29%2B32%281%29%2B40\" Square \"1\" to get \"1\".\r
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\n" ); document.write( "\n" ); document.write( "\"s=-16%2B32%281%29%2B40\" Multiply \"-16\" and \"1\" to get \"-16\".\r
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\n" ); document.write( "\n" ); document.write( "\"s=-16%2B32%2B40\" Multiply \"32\" and \"1\" to get \"32\".\r
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\n" ); document.write( "\n" ); document.write( "\"s=56\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the max height is 56 feet.
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