document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176977>Question 176977</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A boat on the Hudson River travels the same distance in 1/2 hour downstream as it can going upstream for an hour. If the boat travels 12 mph in still water, what is the speed of the current?\r<BR>\n" );
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document.write( "Please help! There are no examples like this one in the book.<BR>\n" );
document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #132025 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=132025\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A boat on the Hudson River travels the same distance in 1/2 hour downstream as it can going upstream for an hour. If the boat travels 12 mph in still water, what is the speed of the current? <BR>\n" );
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document.write( "Downstream DATA:<BR>\n" );
document.write( "time = 1/2 hr ; rate = (12+c) mph ; distance = rt = (1/2)(12+c) = 6 + c/2 miles<BR>\n" );
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document.write( "Upstream DATA:<BR>\n" );
document.write( "time = 1 hr ; rate = (12-c) mph ; distance = rt = 1(12-c) mph<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "distance up = distance down<BR>\n" );
document.write( "6 + c/2 = 12 - c<BR>\n" );
document.write( "(3/2)c = 6<BR>\n" );
document.write( "c = 4 mph (speed of the current)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "  </SPAN>\n" );
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