document.write( "Question 176974: Find n so that nC3=nP2 \n" ); document.write( "
Algebra.Com's Answer #132022 by stanbon(75887)\"\" \"About 
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Find n so that nC3=nP2\r
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\n" ); document.write( "n!/[(n-3)!*3!] = n!/(n-2)!\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by n! to get:
\n" ); document.write( "1/[(n-3)!*6] = 1/(n-2)!\r
\n" ); document.write( "\n" ); document.write( "Invert to get:\r
\n" ); document.write( "\n" ); document.write( "6(n-3)! = (n-2)*(n-3)!\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by (n-3)! to get:\r
\n" ); document.write( "\n" ); document.write( "6 = (n-2)
\n" ); document.write( "n = 8
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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