document.write( "Question 176963This question is from textbook
\n" ); document.write( ": Multiply: x(x+1)(x-1) \n" ); document.write( "
Algebra.Com's Answer #132011 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
First, let's multiply out \"%28x%2B1%29%28x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B1%29%28x-1%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Now let's FOIL the expression.\r
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\n" ); document.write( "\n" ); document.write( "Remember, when you FOIL an expression, you follow this procedure:\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%28x%29%2B1%29%28highlight%28x%29-1%29\" Multiply the First terms:\"%28x%29%2A%28x%29=x%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%28x%29%2B1%29%28x%2Bhighlight%28-1%29%29\" Multiply the Outer terms:\"%28x%29%2A%28-1%29=-x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Bhighlight%281%29%29%28highlight%28x%29-1%29\" Multiply the Inner terms:\"%281%29%2A%28x%29=x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2Bhighlight%281%29%29%28x%2Bhighlight%28-1%29%29\" Multiply the Last terms:\"%281%29%2A%28-1%29=-1\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-x%2Bx-1\" Now collect every term to make a single expression.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-1\" Now combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"%28x%2B1%29%28x-1%29\" FOILs to \"x%5E2-1\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%28x%2B1%29%28x-1%29=x%5E2-1\".\r
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\n" ); document.write( "\n" ); document.write( "So this means that \"x%28x%2B1%29%28x-1%29=x%28x%5E2-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x%5E2-1%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3-x\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"x%28x%2B1%29%28x-1%29=x%5E3-x\"
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