document.write( "Question 176886: Can you explain and show how to graph the point-slope form equation y + 5 = -(x - 2). I understand that the (x,y)is my \"starting\" point and the slope is actually -1/1; however my line is in quadrants 1 and 3 instead of Q 1 & 3. . .what is correct (x,y?) Why is it not (2,5). I.E, if the equation was y - 5 = -2/3 (x + 2),then (2,5) would be correct, right? Thanks in advance for your assistance. \n" ); document.write( "

Algebra.Com's Answer #132007 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Can you explain and show how to graph the point-slope form equation:
\n" ); document.write( "y + 5 = -(x - 2)
\n" ); document.write( "Arrange the equation in the y = form
\n" ); document.write( "removing the brackets changes the signs to
\n" ); document.write( "y + 5 = -x + 2
\n" ); document.write( "y = -x + 2 - 5
\n" ); document.write( "y = -x - 3; the correct values for x,y are which ever satisfy this equation
\n" ); document.write( ":
\n" ); document.write( "choose two x values to substitute in this equation, find y
\n" ); document.write( " x = -6 then y = +3
\n" ); document.write( " x = +3 then y = -6
\n" ); document.write( "join these two points with a straight line
\n" ); document.write( ":
\n" ); document.write( "should look like this
\n" ); document.write( " $\"+graph%28+300%2C+200%2C+-8%2C+8%2C+-8%2C+8%2C+-x-3%29+\"$ \n" ); document.write( "

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