document.write( "Question 176867This question is from textbook
\n" ); document.write( ": Carlos can travel 40 mi on his motorbike in the same time it takes Paul to travel 15 mi on his bicycle. If Paul rides his bike 20 mi/h slower than Carlos rides his motorbike, find the speed for each bike. \n" ); document.write( "
Algebra.Com's Answer #131959 by ankor@dixie-net.com(22740)\"\" \"About 
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Carlos can travel 40 mi on his motorbike in the same time it takes Paul to
\n" ); document.write( " travel 15 mi on his bicycle. If Paul rides his bike 20 mi/h slower than
\n" ); document.write( " Carlos rides his motorbike, find the speed for each bike.
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\n" ); document.write( "let s = motorbike speed
\n" ); document.write( "then
\n" ); document.write( "(s-20) = bike speed
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\n" ); document.write( "write a time equation; time = \"dist%2Fspeed\"
\n" ); document.write( "C's travel time = P's travel time
\n" ); document.write( "\"40%2Fs\" = \"15%2F%28s-20%29\"
\n" ); document.write( "cross multiply
\n" ); document.write( "40(s-20) = 15s
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\n" ); document.write( "40s - 800 = 15s
\n" ); document.write( ";
\n" ); document.write( "40s - 15s = 800
\n" ); document.write( "25s = 800
\n" ); document.write( "s = \"800%2F25\"
\n" ); document.write( "s = 32 mph is the motorbike
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\n" ); document.write( "you can find bike speed
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