document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176851>Question 176851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> s=2b+ph<BR>\n" );
document.write( "solve for h when b is area of base; p is perimeter of base; h is height of prism.\r<BR>\n" );
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document.write( "Thanks in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131915 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  s=2b+ph<BR>\n" );
document.write( "solve for h when b is area of base; p is perimeter of base; h is height of prism. <BR>\n" );
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document.write( "\"Solve for\" means to get it on one side of the = by itself.<BR>\n" );
document.write( " s=2b+ph<BR>\n" );
document.write( "ph = s-2b<BR>\n" );
document.write( "h = (s-2b)/p<BR>\n" );
document.write( " </SPAN>\n" );
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