document.write( "Question 176834This question is from textbook Tennessee Prentice Hall Mathematics Algebra I
\n" ); document.write( ": Can you help with my Algebra problems?\r
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\n" ); document.write( "\n" ); document.write( "Q#15 \"a%5E%28n%29%2F3b%5E%28m%29=b%5E3%2F3\"
\n" ); document.write( " Q#29 \"6a%5E-1c%5E-3%2Fd%5E0\"
\n" ); document.write( " Q#30 \"2%5E-3x%5E2z%5E-7\"
\n" ); document.write( " Q#32\"7s%5E0t%5E-5%2F2%5E-1m%5E2\"
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Algebra.Com's Answer #131904 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
Anything raised to the zero power is 1 \"a%5E0+=+1\" for all a. A negative exponent means take the reciprocal, that is: \"a%5E%28-n%29=1%2Fa%5En\", in other words, move the variable from denominator to numerator or from numerator to denominator and change the sign.\r
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\n" ); document.write( "\n" ); document.write( "So for your first problem, in order for the a term to go away and remain non-zero, the exponent on a has to be 1, so you can say right off that \"n=1\". The b variable is in the denominator in the left hand fraction and in the numerator in the right hand fraction. That means the 3 exponent on b on the right must have been -3 on the left. \"m=+-3\".\r
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\n" ); document.write( "\n" ); document.write( "You should be able to handle the rest of them by applying the same principles.
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