document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176771>Question 176771</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A rectangle has a perimeter of 46 cm. Its length is 2 cm more than twice its width. Find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131897 by </B><A HREF=/tutors/aboutme.mpl?userid=EMStelley><B>EMStelley(208)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=EMStelley><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=EMStelley><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the width of the rectangle w.  Then if the length is 2 cm more than twice the width, the length can be represented by 2w+2.  Remembering that perimeter is 2L+2W, we have that<BR>\n" );
document.write( "46 = 2(2w+2) + 2w<BR>\n" );
document.write( "46 = 4w + 4 + 2w<BR>\n" );
document.write( "46 = 6w + 4<BR>\n" );
document.write( "42 = 6w<BR>\n" );
document.write( "7 = w<BR>\n" );
document.write( "So the width of the rectangle is 7 cm, and since the length is 2w+2, we have that the length is 2(7)+2 = 16 cm. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );