document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176813>Question 176813</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3in. more than twice its width. If the perimeter of the rectange is 30in., find the dimensions of the rectangle. Choose the answer with the correct equations used to solve this problem. \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131886 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w = width of rectangle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2w+3 = length of rectangle<BR>\n" );
document.write( ".<BR>\n" );
document.write( "2(w + 2w+3) = 30<BR>\n" );
document.write( "2(3w+3) = 30<BR>\n" );
document.write( "6w+6 = 30<BR>\n" );
document.write( "w+1 = 5<BR>\n" );
document.write( "w = 4 inches (width)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "length:<BR>\n" );
document.write( "2w+3 = 2(4)+3 = 8+3 = 11 inches (length)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );