document.write( "Question 176794: Find the value of y:\r
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document.write( "y^2 + 7y + 12 = 0\r
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document.write( "(squaring is allowed [the check mark roofing a number], fraction is allowed [only in the simplest form], and imaginary is allowed [if necessary]) \n" );
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Algebra.Com's Answer #131880 by Alan3354(69443) You can put this solution on YOUR website! Find the value of y: \n" ); document.write( "y^2 + 7y + 12 = 0 \n" ); document.write( "-------------- \n" ); document.write( "(y+3)*(y+4) = 0 \n" ); document.write( "y = -3 \n" ); document.write( "y = -4 \n" ); document.write( " \n" ); document.write( " |