document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24707>Question 24707</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given a polynomial and one of it's factors,find the remaining factors of the polynomial.Some factors may not be binomials.<BR>\n" );
document.write( "solve for three x cubed plus ten x squared minus x minus twelve divided by x plus three. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13185 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for three x cubed plus ten x squared minus x minus twelve divided by x plus three.<BR>\n" );
document.write( "N.R.=F(X)=3X^3+10X^2-X-12...WE FIND THAT WHEN X=1 ,F(X)=0..HENCE X-1=0..SO DIVIDING BY X-1 USING SHORT DIVISION ...<BR>\n" );
document.write( "1...|...3..........10...........-1..............-12<BR>\n" );
document.write( "....|...0...........3...........13...............12<BR>\n" );
document.write( "---------------------------------------------------------<BR>\n" );
document.write( "....|...3..........13...........12................0<BR>\n" );
document.write( "SO THE QUOTIENT IS 3X^2+13X+13..NO FURTHER RATIONAL FACTORS ARE POSSIBLE.SINCE B^2-4AC=13^2-4*3*13=169-156=13 IS NOT A PERFECT SQUARE.<BR>\n" );
document.write( "SO N.R./D.R.=(X-1)*(3X^2+13X+13)/(X+3)<BR>\n" );
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