document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176742>Question 176742</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am a bit overwhelmed by the complexity of this question.  Please help me to understand and answer the question.\r<BR>\n" );
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document.write( "If matrix A is transformed into matrix B by means of an elementary row operation, is there an elementary row operation that transforms B into A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131842 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are three elementary row operations:\r<BR>\n" );
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document.write( "1.  Switching the position of two rows.  Obviously, you can just switch them back again.\r<BR>\n" );
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document.write( "2.  Multiplying each element of a row by a non-zero constant.  Just multiply that row by the reciprocal of the non-zero constant.\r<BR>\n" );
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document.write( "3.  Replacing a row with the sum of that row and a multiple of another row.  Just subtract the multiple again.\r<BR>\n" );
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document.write( "So, the answer to your question is yes. </SPAN>\n" );
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